CliffsNotes GRE General Test Cram Plan 2nd Edition (Cliffsnotes Cram Plan)
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Whether you have two months, one month, or even just a week left before the exam, you can turn to the experts at CliffsNotes for a trusted and achievable cram plan to ace the GRE General Test—without ever breaking a sweat!
First, you'll determine exactly how much time you have left to prepare for the exam. Then, you'll turn to the two-month, one-month, or one-week cram plan for week-by-week and day-by-day schedules of the best way to focus your study according to your unique timeline.
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Diagnostic test–helps you pinpoint your strengths and weaknesses so you can focus your review on the topics in which you need the most helpSubject reviews–cover everything you can expect on the actual exam: text completions, sentence equivalences, vocabulary, reading comprehension, analytical writing, arithmetic, algebra, geometry, and applications
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for N or P, it is enough to express the relationship between N and P. Cross-multiply and simplify, and work toward an equation with P) → 80N + 70P = 76N + 76P → 4N = 6P. Then on one side. 80N + 70P = 76(N + . (See Chapter XIII, Section A.) 50. $10.23 It’s possible to calculate each day’s addition to savings and then add, but it may be faster to look for a pattern in the cumulative sum. On day 1, she deposits 1¢, for a total of 1¢. On day 2, she deposits 2¢ for a total of 3¢. On day 3, she
for this reading passage. Although some of the other options may be true statements based on the information presented, Choice A is the best, because the passage is primarily about how conifers adapt and thrive in this environment. 2. A Conifer needles have a waxy coating that protects against moisture loss, so these trees can live in an environment without a lot of rain water. The other answers are not true—conifers shed their needles every three or four years, not annually; the stomata does
condenses two statements: 5x + 4 ≥ –1 (or –1 ≤ 5x + 4) and 5x + 4 ≤ 19. Solving a compound inequality requires solving each of the inequalities it contains. EXAMPLE: Solve –1 ≤ 5x + 4 ≤ 19. See the compound inequality as two simple inequalities: –1 ≤ 5x + 4 and 5x + 4 ≤ 19. Solve each inequality. If desired, the two solutions can be condensed into a compound inequality: –1 ≤ x ≤ 3. 8. Absolute Value Inequalities When an equation contains an absolute value expression, two cases must be
9. 4. C Remove the parentheses by distributing. Add 12z to both sides to eliminate a variable term, and then add 10 to both sides to eliminate a constant term. Finally, divide both sides by –2. 5. B On the left side, “distribute the negative”—that is, multiply by –1—and combine like terms. On the right side, distribute the –4. 128 Algebra Add 4y to both sides, then subtract 2 from both sides, and finally divide both sides by 2. 6. A Don’t be distracted by the use of letters rather than
is expressed in ax2 + bx + c form. Answers 1. A 24x5 – 32x8 = 8x5(3 – 4x3), so c – b = 4 – 3 = 1 and c – a = 4 – 8 = –4. 2. B (–2x – 3)(2x + 5) = –4x2 – 10x – 6x – 15 = –4x2 – 16x – 15, so b = –16 and c = –15. 3. C –3t3(2t – 1) = (–3t3)(2t) – (–3t3)(1) = –6t4 + 3t3. 4. A (5x + 3)(2x – 1) = (5x)(2x) + (5x)(–1) + 3(2x) + 3(–1) = 10x2 – 5x + 6x – 3 = 10x2 + x – 3. 5. D Recognize this as the sum and difference of the same two terms, and, therefore, equal to the difference of squares: . 6. D Look